If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-23x^2+92=0
a = -23; b = 0; c = +92;
Δ = b2-4ac
Δ = 02-4·(-23)·92
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8464}=92$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-92}{2*-23}=\frac{-92}{-46} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+92}{2*-23}=\frac{92}{-46} =-2 $
| p/3-15=-2 | | 3y-4×=5 | | 12y=8y+24 | | 1-4v=25 | | x=22(-x)+3(-x)+x+10 | | 2(r+5-4(r-1)=32 | | 22=5q+3q-q+8 | | 4(4-7p)=-5p+39 | | 2x+44=2 | | w/17+15=15 | | 5x-1=1x-9 | | 4−2x=−3x−3 | | 10=x+5/3 | | 56-u=206 | | 12=x(-18) | | (y+5/y)=(10/8) | | 6x-7=12-7x | | (3x+7)+(8x-5)=90 | | 5p+2+8p-18=90 | | 36=x+7+6x+1 | | y-17/3=-4 | | 45-0.5x=1x+15 | | 3+2=3z-(2z-3) | | -4.9y+5.35=-6.1y-8.93 | | 16/25-x²=0 | | 3y-10+9=2y-1 | | p-3/4=4 | | (5x-4)(4x-4)=0 | | -8+x/3=-13 | | r/5+6=6 | | -3-4=3(4-2m)+3m | | 45-0.5x=15+1 |